In $\Delta ABC$, $E$ is the midpoint of $AC$. $AD$ and $BE$ intersect at $F$, which is t

Question

In $\Delta ABC$, $E$ is the midpoint of $AC$. $AD$ and $BE$ intersect at $F$, which is the midpoint of $BE$. $FC$ and $EH$ intersect at $G$. Given that $AD$ is parallel to $EH$, prove that $EH=2FD$. Hence, show that $AF=3FD$.

Accepted Answer

(i) EH = 2FD (proved); (ii) AF = 3FD (proved).

Proofs in Plane Geometry - Midpoint Theorem

Proofs in Plane Geometry - Midpoint Theorem

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