Scale factor lab

<p>In trapezium \(ABCD\), \(AD\) is parallel to \(BC\). The diagonals \(AC\) and \(BD\) intersect at \(O\). \(POQ\) is a straight line that is parallel to \(AD\) and \(BC\). Prove that</p>
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<ol class="i-list"><li data-list-item-id="item-i" data-list-item-path="item-i"><div class="list-item-paragraph">\(\frac{1}{PO} = \frac{1}{AD} + \frac{1}{BC}\),</div></li><li data-list-item-id="item-ii" data-list-item-path="item-ii"><div class="list-item-paragraph">\(PO = OQ\), and</div></li><li data-list-item-id="item-iii" data-list-item-path="item-iii"><div class="list-item-paragraph">\(PQ = \frac{2AD \times BC}{AD + BC}\).</div></li></ol>

In trapezium \(ABCD\), \(AD\) is parallel to \(BC\). The diagonals \(AC\) and \(BD\) intersect at \(O\). \(POQ\) is a straight line that is parallel to \(AD\) and \(BC\). Prove that

Proofs in Plane Geometry - Similarity

Proofs in Plane Geometry - Similarity

Video Solution:

Solution:

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