Let \\({\\mathrm{f} \\circ \\mathrm{g}(x) = \\mathrm{f}[\\mathrm{g}(x)]}\\). Show that \\({[\\mathrm{f} \\circ \\mathrm{g}(x)]' = \\mathrm{f}'[\\mathrm{g}(x)]\\mathrm{g}'(x)}

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Proof of the Chain Rule of Differentiation

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