Products of functions
Products of functions
7 marks
TGM Original
Given y=x2 ln(x2 + 1), find dydx. Show that the gradient is positive for x>0.
Solution:
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Answer:\(\dfrac{\mathrm{d}y}{\mathrm{d}x}=\dfrac{2 x^{3}}{x^{2} + 1} + 2 x \ln{\left(x^{2} + 1 \right)}\) The gradient is positive for \(x>0\).
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