In the diagram, $ABD$ is a straight line, $AB=10$ cm, $BC=6$ cm and angle $BCD$ is a right a

Question

In the diagram, $ABD$ is a straight line, $AB=10$ cm, $BC=6$ cm and angle $BCD$ is a right angle. Given that $\angle CBD=x$, where $\sin x=0.6$, $\cos x=0.8$and $\tan x=0.75$, calculate the length of $BD$, the value of $\sin \angle ABC$, the area of triangle $ABC$. Tip: 1. For intermediate working, correct them to $5$ significant figures to maintain accuracy of answers 2. For answers in degree, correct to $1$ decimal places. 3. For other answers, correct to $3$ significant figures.

Accepted Answer

(i) $7.5\text{ cm}$ (ii) $0.6$ (iii) $18\text{ cm}^2$

Problem involving the Area of a Triangle

Problem involving the Area of a Triangle

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