First player to roll a six

First player to roll a six

IP 4
9 marks

Ali and Bala take turns to roll a fair six-sided die, with Ali rolling first. The first person to roll a six wins, and the game stops.

  1. Let \(p\) be the probability that Ali wins. Explain why, if neither player rolls a six in the first round of one roll each, the game is in the same position as at the start. Hence show that \(p=\dfrac{1}{6}+\dfrac{25}{36}p\), and find \(p\).[4]
  2. In a different game of the same kind, each roll succeeds with probability \(q\), where \(0<q<1\). Show that the probability that the first player wins is \(\dfrac{1}{2-q}\).[3]
  3. Explain why the first player always has the better chance of winning, and describe what happens to this advantage as \(q\) becomes very small.[2]

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs tuition enrolment.

Create a free account to practise similar questions.

Answer:(a) \(p=\dfrac{6}{11}\) (b) shown (c) \(\dfrac{1}{2}\lt\dfrac{1}{2-q}\lt 1\) for \(0\lt q\lt 1\); the advantage tends to zero as \(q\to0\)

Need help? Join our IP Math tuition programme.

Learn more