Probability of an event that is twice as likely as an independent event, given the probability of their union

Probability of an event that is twice as likely as an independent event, given the probability of their union

6 marks

Two independent events \(C\) and \(D\) satisfy \(\mathrm{P}(D)=2\,\mathrm{P}(C)\) and \(\mathrm{P}(C\cup D)=0.805\). Find \(\mathrm{P}(D)\).[6]

Solution:

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Answer:\(\mathrm{P}(D)=0.7\)

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