Probability distribution whose probabilities are proportional to the terms of an arithmetic sequence

Probability distribution whose probabilities are proportional to the terms of an arithmetic sequence

6 marks

The terms of an arithmetic sequence satisfy \(u_2=0.7\) and \(u_5=0.1\).

  1. Find \(d\), the common difference of the sequence.[2]

A discrete random variable \(Y\) takes the values \(1\), \(2\), \(3\), \(4\) and \(5\), with \(\mathrm{P}(Y=n)=\frac{u_n}{k}\) for each value \(n\), where \(k\) is a positive constant. Its probability distribution is given in the table.

\(n\)\(1\)\(2\)\(3\)\(4\)\(5\)
\(\mathrm{P}(Y=n)\)\(\frac{u_1}{k}\)\(\frac{0.7}{k}\)\(\frac{u_3}{k}\)\(\frac{u_4}{k}\)\(\frac{0.1}{k}\)
  1. Find \(k\).[4]

Solution:

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Answer:(a) \(d=-0.2\) (b) \(k=2.5\)

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