Probability

Probability

Secondary 4

A fair six-sided die is rolled.
Let \(E\) be “an even number” and \(P\) be “a prime number”.
A student calculates:
\[ P(E\cup P)=\frac36+\frac36=1. \]

  1. List \(E\), \(P\), and their common outcomes.

  2. Explain the error.

  3. Find the correct probability of \(E\cup P\).

  4. Find the probability of neither event.

Solution:

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Answer:(a) \(E=\{2,4,6\}\), \(P=\{2,3,5\}\), overlap \(\{2\}\); (b) double-counted \(2\); (c) \(\frac{5}{6}\); (d) \(\frac{1}{6}\).

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