A biased five-sided spinner
A biased five-sided spinner
Secondary 2
6 marks
TGM Original Questions
A biased spinner has the table:
| Number | \(1\) | \(2\) | \(3\) | \(4\) | \(5\) |
|---|---|---|---|---|---|
| Probability | \(\frac{1}{4}\) | \(x\) | \(\frac{1}{5}\) | \(\frac{1}{10}\) | \(x\) |
- Find \(x\).[2]
- Find the probability of
- 2 or 3,[1]
- an odd number,[1]
- a number not more than 4.[1]
- In 80 spins, find the expected number of results equal to 3 or 4.[1]
Solution:
Solution locked
680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs a course plan.
Create a free account to practise similar questions.
Answer:(a) \(x=\frac{9}{40}\) (b)(i) \(\frac{17}{40}\) (ii) \(\frac{27}{40}\) (iii) \(\frac{31}{40}\) (c) \(24\).
Need help? Join our E-Maths tuition for O-Level success.
Learn more