<p>Consider two events, \(A\) and \(B\).<br>It is given that&nbsp;\(\mathrm{P}(a \cup B') = \frac{5 + x}{24}, \mathrm{P}(A \cup B) = \frac{7 - x}{12}\) and \(\mathrm{P}(A' \cup B) = \frac{1}{6}\), where&nbsp;\(0 \leq x \leq 7\).</p>
<ol class="abc-list"><li data-list-item-id="item-1791203431420-yrycdn9q6" data-list-item-path="item-1791203431420-yrycdn9q6"><div class="list-item-paragraph"><p>Show that \(\mathrm{P}(A) = \frac{19 - x}{24}\).</p><span class="inline-marks">[2]</span></div></li></ol>
<p>It is given that&nbsp;\(A\) and \(B\) are independent.</p>
<ol class="abc-list" start="2"><li data-list-item-id="item-1791203472058-cpa8m6ywb" data-list-item-path="item-1791203472058-cpa8m6ywb"><div class="list-item-paragraph"><p>Find the possible values of \(x\).</p><span class="inline-marks">[6]</span></div></li></ol>

Consider two events, \(A\) and \(B\).
It is given that \(\mathrm{P}(a \cup B') = \frac{5 + x}{24}, \mathrm{P}(A \cup B) = \frac{7 - x}{12}\) and \(\mathrm{P}(A' \cup B) = \frac{1}{6}\), where \(0 \leq x \leq 7\).

<p>Show that \(\mathrm{P}(A) = \frac{19 - x}{24}\).</p>

It is given that \(A\) and \(B\) are independent.

<p>Find the possible values of \(x\).</p>

Probability

International Baccalaureate Mathematics: Analysis and Approaches Standard Level

2026 MAY TZA P1 Q6

2026 MAY TZA P1 Q6