The intersection \(A\cap B\) is the event that both \(A\) and \(B\) occur. The union \(A\cup B\) is the event that at least one of \(A\) or \(B\) occurs.
Only \(A\cap B\) is shaded.
All of \(A\cup B\) is shaded.
\[P(A\cup B)=P(A)+P(B)-P(A\cap B)\]
\[P(A\cup B\cup C)=P(A)+P(B)+P(C)-P(A\cap B)-P(B\cap C)-P(A\cap C)+P(A\cap B\cap C)\]
De Morgan's laws
\[(A\cup B)'=A'\cap B',\qquad (A\cap B)'=A'\cup B'\]\[P((A\cup B)')=1-P(A\cup B)=P(A'\cap B')\]\[P((A\cap B)')=1-P(A\cap B)=P(A'\cup B')\]
\(P(A\cup B)\)
\(P(A\cap B)\)
\(P(A'\cap B')\)
\(P(A'\cup B')\)
Example
If \(P(A)=0.5\), \(P(B)=0.4\) and \(P(A\cup B)=0.7\), then \(P(A\cap B)=0.5+0.4-0.7=0.2\) and \(P(A'\cap B')=1-0.7=0.3\).
Exam check: every region of the Venn diagram must be non-negative and the regions must add to \(1\); here \(0.3+0.2+0.2+0.3=1\).
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