Probability

Probability

IP 4

You are given:
\[P(A)=0.45,\qquad P(B)=0.35,\qquad P(A\cap B)=0.15.\]Find:

  1. \(P(A\cup B)\);

  2. the probability that neither occurs;

  3. the probability that exactly one occurs.

Solution:

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Answer:(a) \(0.65\). (b) \(0.35\). (c) \(0.50\).

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