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Probability

Probability

IP 4

A box contains \(8\) working bulbs and \(2\) faulty bulbs. Two bulbs are selected without replacement.

  1. Find the probability that both work.

  2. Find the probability that exactly one is faulty.

  3. Given that the first bulb is faulty, find the probability that the second works.

Solution:

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Answer:(a) \(\frac{28}{45}\). (b) \(\frac{16}{45}\). (c) \(\frac89\).

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