Probabilities of two events for two spins of a fair five-sector spinner and the probability of their union

Probabilities of two events for two spins of a fair five-sector spinner and the probability of their union

6 marks

A fair spinner has five equal sectors numbered \(1\), \(2\), \(3\), \(4\) and \(5\). The spinner is spun twice. The events \(G\) and \(H\) are defined as follows.

\(G\): both scores are odd numbers.

\(H\): the two scores add up to \(6\).

Find

  1. \(\mathrm{P}(G)\),
  2. \(\mathrm{P}(H)\),
  3. \(\mathrm{P}(G\cup H)\).

[6]

Solution:

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Answer:(a) \(\dfrac{9}{25}\) (b) \(\dfrac15\) (c) \(\dfrac{11}{25}\)

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