In the diagram, $BE=AD$, $AE=BD$ and $\angle ACE=76{}^\circ$. Show that $\Delta ABE$ an

Question

In the diagram, $BE=AD$, $AE=BD$ and $\angle ACE=76{}^\circ$. Show that $\Delta ABE$ and $\Delta BAD$ are congruent. Find $\angle ABE$. Name another pair of congruent triangles.

Accepted Answer

$\text{(i)}\ \triangle ABE\equiv\triangle BAD\text{ (SSS)}$ $\text{(ii)}\ 38^\circ$ $\text{(iii)}\ \triangle ACE\equiv\triangle BCD\text{ (AAS)}$

Principles of Triangle Congruence: Applications in Quadrilaterals and Polygons

Principles of Triangle Congruence: Applications in Quadrilaterals and Polygons

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