Principles of Plane Geometry: Triangle Properties and Proofs

Principles of Plane Geometry: Triangle Properties and Proofs

Secondary 3

In the diagram, \(PCBQ\) is a straight line. \(AB=15\) cm, \(\sin \ \angle ABC=\frac{1}{2}\) and \(\sin \ \angle ACP=\frac{1}{3}\).

  1. Write down the value of \(\sin \ \angle ACB\).
  2. Calculate the length of \(AC\).

Video Solution:

Video Solution

Video solution locked

A free account saves your progress; this video needs a course plan.

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs a course plan.

Answer:(i) \(\frac{1}{3}\) (ii) \(22.5\text{ cm}\)

Need help? Join our E-Maths tuition for O-Level success.

Learn more