Written as the product of prime factors $3500=2^{2} imes 5^{3} imes 7$. Express $720$ as the produ

Question

Written as the product of prime factors $3500=2^{2}	imes 5^{3}	imes 7$. Express $720$ as the product of its prime factors. Hence write down the largest integer which is a factor of both $3500$ and $720$, the smallest positive integer $k$ for which $720k$ is a multiple of $3500$.

Accepted Answer

(a) $2^4\times3^2\times5$ (b)(i) $20$ (b)(ii) $175$

Prime Factorisation, HCF, and LCM Applications

Prime Factorisation, HCF, and LCM Applications

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