$y=\mathrm{f}\left( x \right)$ $y=\frac{1}{\mathrm{f}\left( x \right)}$ \(y=\mathrm{f}'\left( x

Question

$y=\mathrm{f}\left( x \right)$ $y=\frac{1}{\mathrm{f}\left( x \right)}$ $y=\mathrm{f}'\left( x \right)$

Accepted Answer

For $y=\dfrac1{f(x)}$: vertical asymptotes $x=-5,2$, horizontal asymptote $y=0$, turning point $\left(-1,-\dfrac14\right)$, and point $\left(0,-\dfrac13\right)$. For $y=f'(x)$: zeros $(-1,0)$ and $(2,0)$, negative for $x2$, positive for $-1<x<2$.

Prelims Revision Set: Reciprocal and Gradient Graphs Q2

Prelims Revision Set: Reciprocal and Gradient Graphs Q2

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