$y=\mathrm{f}\left( x \right)$ $y=\frac{1}{\mathrm{f}\left( x \right)}$ \(y=\mathrm{f}'\left( x

Question

$y=\mathrm{f}\left( x \right)$ $y=\frac{1}{\mathrm{f}\left( x \right)}$ $y=\mathrm{f}'\left( x \right)$

Accepted Answer

For $y=\dfrac1{f(x)}$: vertical asymptotes $x=-3,0,3$, horizontal asymptote $y=0$, turning points $\left(-1,\dfrac25\right)$, $\left(1,-\dfrac12\right)$. For $y=f'(x)$: zeros $(-1,0)$, $(1,0)$, positive for $x1$, negative for $-1<x<1$.

Prelims Revision Set: Reciprocal and Gradient Graphs Q1

Prelims Revision Set: Reciprocal and Gradient Graphs Q1

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