Given that $ \mathrm P(x) = x^4 - 4x^3 + ax^2 + bx + 12$ leaves the same remainder when divid

Question

Given that $ \mathrm P(x) = x^4 - 4x^3 + ax^2 + bx + 12$ leaves the same remainder when divided by $x - 1$ and $x + 2$. It is also given that $x - 3$ is a factor of $\mathrm P (x) $. Find the values of $a$ and $b$

Accepted Answer

$a=-3,\ b=14$.

Polynomials, Cubic Equations and Partial Fractions - Remainder and Factor Theorems

Polynomials, Cubic Equations and Partial Fractions - Remainder and Factor Theorems

Solution:

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