Let $f(x)=2x^3-3x+1$. Use the definition of the derivative to find $f'(x)$. Hence find the equat

Question

Let $f(x)=2x^3-3x+1$. Use the definition of the derivative to find $f'(x)$. Hence find the equation of the tangent to $y=f(x)$ at $x=1$.

Accepted Answer

$f'(x)=6x^2-3;\quad y=3x-3$

Polynomial derivative from first principles