Polynomial derivative from first principles
Polynomial derivative from first principles
IB Year 6 | Grade 12
6 marks
Let \(f(x)=2x^3-3x+1\). Use the definition of the derivative to find \(f'(x)\). Hence find the equation of the tangent to \(y=f(x)\) at \(x=1\).[6]
Solution:
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Answer:\(f'(x)=6x^2-3;\quad y=3x-3\)
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