Recognisable Forms and Substitution

Recognisable Forms and Substitution

TGM Original Questions

The H2 syllabus emphasises integrals in which an inner function and its derivative appear together. These forms are consequences of the chain rule.

Core recognisable forms

FormAntiderivativeConditions
\(\displaystyle\int \mathrm{f}'(x)[\mathrm{f}(x)]^n\,\mathrm{d}x\)\(\dfrac{[\mathrm{f}(x)]^{n+1}}{n+1}+C\)\(n\ne-1\)
\(\displaystyle\int \mathrm{f}'(x)e^{\mathrm{f}(x)}\,\mathrm{d}x\)\(e^{\mathrm{f}(x)}+C\)Where the composition is defined
\(\displaystyle\int \dfrac{\mathrm{f}'(x)}{\mathrm{f}(x)}\,\mathrm{d}x\)\(\ln|\mathrm{f}(x)|+C\)\(\mathrm{f}(x)\ne0\) on the interval
Take note

A memorised list of recognisable forms is never exhaustive. Change of variables provides one general method for deriving and checking them.

Change of variables

Let \(u=\mathrm{g}(x)\), where \(\mathrm{g}\) is differentiable and its range is an interval \(I\). If \(\mathrm{f}\) is continuous on \(I\), then

\[\int \mathrm{f}(\mathrm{g}(x))\mathrm{g}'(x)\,\mathrm{d}x=\int \mathrm{f}(u)\,\mathrm{d}u\]

This method is also called substitution or the reverse chain rule.

Substitution sequence

Choose \(u=\mathrm{g}(x)\)
Form \(\mathrm{d}u=\mathrm{g}'(x)\,\mathrm{d}x\)
Rewrite entirely in \(u\), then integrate
  1. Choose \(u\) so that the remaining factors can be written using \(u\) and \(\mathrm{d}u\).
  2. Rewrite the whole integrand; do not mix \(x\) and \(u\) in the transformed integral.
  3. After integrating, substitute back for \(u\) and include \(C\).
Exam check

Change of variables is a mathematically rigorous and accepted H2 A-Level integration method.

Illustrative substitutions

Cancelling Method (u-substitute method)

Simple case: \(\displaystyle\int x(x^2+1) \, \mathrm{d}x = \displaystyle\int x^3 + x \, \mathrm{d}x = \frac{x^4}{4} + \frac{x^2}{2} + c\)

Complex case: \(\displaystyle\int x(x^2+1)^{10} \, \mathrm{d}x\)
Let \(u = x^2 + 1\), \(\displaystyle\frac{\mathrm{d}u}{\mathrm{d}x} = 2x\), \(\mathrm{d}x = \frac{\mathrm{d}u}{2x}\)
\(= \displaystyle\int x \cdot u^{10} \cdot \frac{\mathrm{d}u}{2x} = \frac{1}{2}\displaystyle\int u^{10}\,\mathrm{d}u\) [see MF26]
\(= \displaystyle\frac{1}{22}(x^2+1)^{11} + c\)

More Examples:

• \(\displaystyle\int \sec^2 x (2\tan x + 3)^5 \, \mathrm{d}x\): let \(u = 2\tan x + 3\)
\(= \displaystyle\frac{1}{12}(2\tan x + 3)^6 + c\)

• \(\displaystyle\int \frac{x^2}{x^3-1} \, \mathrm{d}x\): let \(u = x^3 - 1\)
\(= \displaystyle\frac{1}{3}\displaystyle\int \frac{1}{u}\,\mathrm{d}u = \frac{1}{3}\ln|x^3-1| + c\)

• \(\displaystyle\int \frac{e^x}{1+e^x} \, \mathrm{d}x\): let \(u = 1 + e^x\)
\(= \ln|1+e^x| + c\)

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Answer:\(u=g(x):\quad\int f(g(x))g'(x)\,\mathrm dx=\int f(u)\,\mathrm du\)

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