Core stretch Points $E,B,D$ are collinear. Given $BD=10$ cm, $BC=12$ cm, \(\angle CEB=\angle A

Question

Core stretch Points $E,B,D$ are collinear. Given $BD=10$ cm, $BC=12$ cm, $\angle CEB=\angle ABD=90^\circ$, $\angle ADB=40^\circ$ and $\angle CBD=130^\circ$, calculate $AB$, $CE$, the area of $\triangle BCD$. You may use $\sin40^\circ=0.643$, $\cos40^\circ=0.766$, $\tan40^\circ=0.839$, $\sin50^\circ=0.766$, $\cos50^\circ=0.643$. $10$ $12$ $C$ $D$ $B$ $A$ $E$ $40^\circ$ $130^\circ$ Give non-exact lengths and areas to 3 significant figures, and angles to 1 decimal place.

Accepted Answer

(a) $8.39$ cm (b) $9.19$ cm (c) $46.0\text{ cm}^2$.

Two right triangles around a straight line

Two right triangles around a straight line

Solution:

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