Triangle $ABD$ is right-angled at $B$, with $AB=15$ cm and $AD=17$ cm. Triangle $BCD$ is i

Question

Triangle $ABD$ is right-angled at $B$, with $AB=15$ cm and $AD=17$ cm. Triangle $BCD$ is isosceles with $BC=CD=10$ cm. Find $15$ $17$ $10$ $10$ $A$ $B$ $D$ $C$ Give non-exact lengths and areas to 3 significant figures, and angles to 1 decimal place.

Accepted Answer

(a) $8$ cm (b) $15/17$ (c) $8\sqrt{21}\approx36.7\text{ cm}^2$.

A right triangle joined to an isosceles triangle

A right triangle joined to an isosceles triangle

Solution:

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