Perfect Square Quadratics

Perfect Square Quadratics

Secondary 3

If \({{x}^{2}}+10x+m\) is a perfect square, find the value of \(m\).
Hence, solve the equation \({{x}^{2}}+10x+m=0\) giving your answers correct to \(2\) decimal places.

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Answer:(i) m = 25; (ii) x = -5.

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