A particle has velocity v=3-t m,s-1 for 0 <= t 5 seconds and initial displacement -1 m. Sketch its displacement–time and distance–time graphs, labelling endpoint and turning values. Mark its time at the origin and its rest time, and find its total distance.
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Answer:Origin at \(t=3-\sqrt7\) s; rest at \(3\) s. Position values at \(0,3,5\) s are \(-1,\dfrac{7}{2},\dfrac{3}{2}\) m; distances are \(0,\dfrac{9}{2},\dfrac{13}{2}\) m. Total distance \(\dfrac{13}{2}\) m.