A seat on an observation wheel is \(4\) metres above the ground at its lowest point at 10:00 am. It next reaches its lowest point at 10:16 am. The centre of the wheel is \(18\) metres above the ground.
Let \(t\) be the number of minutes after 10:00 am. The seat's height \(h(t)\), in metres, is modelled by \(h(t)=a\cos\bigl(b(t-c)\bigr)+18\), where \(a\), \(b\) and \(c\) are positive constants.
680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs tuition enrolment.
Create a free account to practise similar questions.
Need help? Join our JC Math tuition classes.
Learn more