Obtaining unknown mean and variance

Obtaining unknown mean and variance

IB Year 6 | Grade 12

\(X\) is a normal variable with mean \(\mu\) and standard deviation \(\sigma\). It is given that \(P(X > 128) = 0.15\) and that \(P(X > 97) = 0.875\). Calculate \(\mu\) and \(\sigma\).

Solution:

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Answer:\(\mu=113.3074409\ldots\), \(\sigma=14.17607658\ldots\) (so \(\mu=113.3\), \(\sigma=14.2\) to 1 d.p.).

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