Normal and branch restriction of a trigonometric curve
Normal and branch restriction of a trigonometric curve
Junior College 2
7 marks
A curve is defined parametrically by \(x=3\tan t\) and \(y=2\sec t\), where \(-\frac{\pi}{2}<t<\frac{\pi}{2}\).
Using calculus, find the gradient of the normal to the curve at the point where \(t=\frac{\pi}{6}\).[3]
Eliminate \(t\) to obtain a Cartesian equation of the curve, stating any restriction on \(y\). Explain why the Cartesian equation alone includes points that do not belong to the parametric curve.[4]
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Answer:(a) Normal gradient \(=-3\) (b) \(\frac{y^2}{4}-\frac{x^2}{9}=1\), \(y\geq2\)