Relative to an origin \(O\), the position vectors of points \(A\) and \(B\) are \(\mathbf{a}\) and \(\mathbf{b}\) respectively. The two non-zero vectors \(\mathbf{a}\) and \(\mathbf{b}\) satisfy the equation \(\mathbf{a}=\left( \mathbf{a}\cdot \mathbf{b} \right)\mathbf{b}\).
A third point \(C\) has position vector \(\mathbf{c}\). It is further given that \(\mathbf{a}\cdot \mathbf{b}=-2\) and \(\mathbf{c}\cdot \left( \mathbf{c}+\mathbf{b} \right)=3\).
Another point \(D\) lies on \(CA\) produced such that \(CD=4CA\).
Video solution locked
A free account saves your progress; this video needs tuition enrolment.
680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs tuition enrolment.
Create a free account to practise similar questions.
Need help? Join our JC Math tuition classes.
Learn more