Use calculus to find the volume generated when the line \(y=kx\), for \(0\leq x\leq h\), is rotated through \(2\pi\) radians about the \(x\)-axis.[3]
Hence show that the volume of a cone of height \(h\) and base radius \(r\) is \(\dfrac{1}{3}\pi r^2h\).[1]
The straight line \(y=kx\) cuts the curve \((x-k)^2+y^2=k^2\) at the point where \(x=0.6\). Find exactly the possible values of \(y\) at this point.[3]
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