Without using a calculator, solve the inequality $\frac{4}{x + 2} \geqslant \frac{x - 3}{x}$.[4] H

Question

Without using a calculator, solve the inequality $\frac{4}{x + 2} \geqslant \frac{x - 3}{x}$.[4] Hence, solve the inequality $\frac{4}{\vert{}x\vert{} + 2} \geqslant \frac{\vert{}x\vert{} - 3}{\vert{}x\vert{}}$.[2]

Accepted Answer

(a) $-2<x\le-1$ or $0<x\le6$ (b) $-6\le x<0$ or $0<x\le6$

N2024 P1 Q4

N2024 P1 Q4

Video Solution:

Solution 1