N2020 P1 Q9

N2020 P1 Q9

12 marks
Past Year National Exams
Free
  1. By considering the gradients of two lines, explain why \({{\tan }^{-1}}(2)-{{\tan }^{-1}}\left( -\frac{1}{2} \right)=\frac{1}{2}\pi \).[1]

The curves \({{C}_{1}}\) and \({{C}_{2}}\) have equations \(y=\frac{1}{{{x}^{2}}+1}\) and \(y=\frac{k}{3x+4}\) respectively, where \(k\) is a constant and \(k>0\).

  1. Find the set of values of \(k\) such that \({{C}_{1}}\) and \({{C}_{2}}\) intersect.[3]

It is now given that \(k=2\).

  1. Sketch \({{C}_{1}}\) and \({{C}_{2}}\) on the same graph, giving the coordinates of any points where \({{C}_{1}}\) or \({{C}_{2}}\) cross the axes and the equations of any asymptotes.[3]
  2. Find the exact area of the region bounded by \({{C}_{1}}\) and \({{C}_{2}}\), simplifying your answer.[5]

Video Solution:

Default solution

Timothy Gan
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Answer:(ii) \({\left\{ k \in \mathbb{R} : -\frac{1}{2} \le k \le \frac{9}{2} \right\}}\) (iv) \({\frac{1}{2}\pi - \frac{4}{3}\ln 2}\)

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