N2019 P2 Q1

N2019 P2 Q1

6 marks
Past Year National Exams
Free

You are given that \(I=\displaystyle\displaystyle \displaystyle\int{x{{\left( 1-x \right)}^{\frac{1}{2}}}}\mathrm{d}x\).

  1. Use integration by parts to find an expression for \(I\).[2]
  2. Use the substitution \({{u}^{2}}=1-x\) to find another expression for \(I\).[2]
  3. Show algebraically that your answers to parts (i) and (ii) differ by a constant.[2]

Video Solution:

Default solution

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Answer:(i) -2x(1-x)^(3/2)/3 - 4(1-x)^(5/2)/15 + C₁; (ii) -2(1-x)^(3/2)/3 + 2(1-x)^(5/2)/5 + C₂; (iii) Difference = constant D (shown equivalent)

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