The events \(A\), \(B\) and \(C\) are such that \(P(A)=a\), \(\mathrm{P}\left( B \right)=b\) and \(\mathrm{P}\left( C \right)=c\). \(A\) and \(B\) are independent events. \(A\) and \(C\) are mutually exclusive events.
You are now given that \(A'\) and \(C'\) are not mutually exclusive, \(P(A)=\frac{2}{5}\), \(\mathrm{P}\left( B\cap C \right)=\frac{1}{5}\) and \(\mathrm{P}\left( A'\cap B'\cap C' \right)=\frac{1}{10}\).



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