Given that ${{x}^{2}}-{{y}^{2}}+2xy+4=0$, find $\frac{\mathrm{d}y}{\mathrm{d}x}$ in terms of $x$ and

Question

Given that ${{x}^{2}}-{{y}^{2}}+2xy+4=0$, find $\frac{\mathrm{d}y}{\mathrm{d}x}$ in terms of $x$ and $y$. [4] For the curve with equation ${{x}^{2}}-{{y}^{2}}+2xy+4=0$, find the coordinates of each point at which the tangent is parallel to the $x$-axis. [4]

Accepted Answer

$\frac{dy}{dx} = \frac{y+x}{y-x}$; points: $(\sqrt{2}, -\sqrt{2})$ and $(-\sqrt{2}, \sqrt{2})$

N2010 P1 Q4

N2010 P1 Q4

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