Mixed Trigonometry: Altitude to Hypotenuse in \(PQR\)

Mixed Trigonometry: Altitude to Hypotenuse in \(PQR\)

Secondary 2

In \(\Delta PQR\), \(PQ=6.4\) m, \(\angle QPR=90{}^\circ \) and \(\angle PQR=71{}^\circ \). \(Y\) lies on \(QR\) such that \(PY\) is perpendicular to \(QR\).

Find the length of

  1. \(PY\),
  2. \(YR\).

Video Solution:

Video Solution

Video solution locked

A free account saves your progress; this video needs a course plan.

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs a course plan.

Answer:(i) \(PY=6.05\text{ m}\) (ii) \(YR=17.6\text{ m}\)

Need help? Join our E-Maths tuition for O-Level success.

Learn more