In \(\triangle ACD\), \(B\) and \(E\) are the midpoints of \(AC\) and \(AD\).
\(BE\parallel CD\qquad BE=\dfrac12CD\)
Proof
The smaller triangle is similar to the whole triangle with scale factor 1 : 2.
Equivalent labelling
If \(M,N\) are the midpoints of \(AB,AC\), then \(MN\parallel BC\) and \(MN=\frac12BC\).
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