Midpoint Theorem

Midpoint Theorem

In the diagram, \(BFD\), \(AFC\) and \(BEC\) are straight lines. It is given that \(AF = FC\), \(BF = FD\), \(BE = EC\). Prove that

\(FE = \frac{1}{2} AB\),
\(AB = DC\).

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Answer:(i) Proved: \(FE=\frac12AB\) (ii) Proved: \(AB=DC\)

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