In the triangle $LMN$, $LN$ is perpendicular to $MN$ and $LN$ is parallel to the vector $\mathbf{u}$

Question

In the triangle $LMN$, $LN$ is perpendicular to $MN$ and $LN$ is parallel to the vector $\mathbf{u}$ which is given by $\left( \begin{matrix} 2\ ,-2\ ,1 \\end{matrix} ight)$. It is given that the points $L$ and $M$ are $(4,2,-1)$ and $(3,6,2)$ respectively Find the length of $LN$. Hence find the length of $MN$.

Accepted Answer

(i) 7/3 units (ii) √185/3 units

MI Lecture Notes Vectors Practice 6

MI Lecture Notes Vectors Practice 6

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