Mensuration (Pyramid, Cones and Spheres) - Volume and Surface Area of Composite Solids

Mensuration (Pyramid, Cones and Spheres) - Volume and Surface Area of Composite Solids

IP 1
5 marks

A solid consists of a cuboid and a rectangular-based pyramid joined along the cuboid’s entire top face (Diagram not drawn to scale). The cuboid measures \(12\text{ cm}\) by \(8\text{ cm}\) by \(7\text{ cm}\). The total vertical height of the solid is \(16\text{ cm}\).

Kai calculates the volume of the solid as
\[12\times8\times7+\frac13\times12\times8\times16.\]

  1. Explain Kai’s mistake.

    [1]
  2. Find the correct volume of the solid.

    [3]
  3. The pyramid’s vertex is moved sideways while its base and perpendicular height remain unchanged. Does the volume of the solid change? Explain your answer.

    [1]

Solution:

Solution locked

Sign in to view the step-by-step solution

Similar questions are unavailable for this question.
Answer:(a) \(16\text{ cm}\) is the total height, not the pyramid’s height. (b) \(960\text{ cm}^3\). (c) No change.

Need help? Join our JC Math tuition classes.

Learn more