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Exponential Integral Involving Absolute Sine Function
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Exponential Integral Involving Absolute Sine Function
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The integral \({{I}_{n}}\) is defined by
\[ I_n = \displaystyle\displaystyle \displaystyle\int_{n\pi}^{(n+1)\pi} e^{-x}\,|\sin x|\,dx, for \quad n \in \mathbb{N}. \]
Show that
\[ I_0 = \frac{1}{2}\left( 1 + e^{-\pi} \right). \]
[6]
By letting \(y = x - n\pi\), show that
\[ I_n = e^{-n\pi} I_0. \]
[4]
Hence determine the exact value of \(\displaystyle\displaystyle \displaystyle\int_{0}^{\infty }{{{\mathrm{e}}^{-x}}\left| \sin x \right|}\mathrm{ d}x\).
[5]
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Answer:
(e^π + 1) / (2(e^π − 1))
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