Show that \(\dfrac{\mathrm{d}}{\mathrm{d}x}\left(\dfrac{3x+2}{\sqrt{x+4}}\right)=\dfrac{3x+22}{

Question

Show that $\dfrac{\mathrm{d}}{\mathrm{d}x}\left(\dfrac{3x+2}{\sqrt{x+4}}\right)=\dfrac{3x+22}{2(x+4)^{3/2}}$.[4] Hence evaluate $\displaystyle\int_{-3}^{5}\dfrac{3x+22}{2(x+4)^{3/2}}\,\mathrm{d}x$.[3]

Accepted Answer

$\dfrac{38}{3}$

Linear numerator over a square root

Linear numerator over a square root

Video Solution:

Solution:

Solution locked