Two linear forms of the same law

Two linear forms of the same law

IP 3
8 marks

The variables \(x\) and \(y\) are related by \(y=\dfrac{a}{x+b}\), where \(a\) and \(b\) are positive constants.

  1. Show that the graph of \(\dfrac{1}{y}\) against \(x\) is a straight line, and state its gradient and intercept in terms of \(a\) and \(b\).[2]
  2. This line has gradient \(0.25\) and vertical intercept \(0.5\). Find \(a\) and \(b\).[2]
  3. Another student plots \(x\) against \(\dfrac{1}{y}\) for the same data. Find the gradient and intercept of her line, and explain why both students obtain the same values of \(a\) and \(b\).[2]
  4. Explain why plotting \(y\) against \(\dfrac{1}{x}\) does not give a straight line.[2]

Solution:

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Answer:(a) gradient \(\dfrac{1}{a}\), intercept \(\dfrac{b}{a}\) (b) \(a=4,\ b=2\) (c) gradient \(4\), intercept \(-2\)

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