A straight line graph is drawn for $\lg \frac{1}{y}$ against $x$ to represent the curve \(\

Question

A straight line graph is drawn for $\lg \frac{1}{y}$ against $x$ to represent the curve $\frac{1}{y} = A^{(x+B)}$. Given that the line passes through the points $(0, 4)$ and $(3, 13)$, find the value of $A$ and $B$. Hence, find the value of $x$ when $\frac{\lg \frac{1}{y}}{x} = 4$.

Accepted Answer

$A = 10^3 = 1000; \quad B = \frac{4}{3}; \quad \text{when } \frac{\lg{\frac{1}{y}}}{x} = 4, x = 4$

Linear Law - Predictions from Linearised Models

Linear Law - Predictions from Linearised Models

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