Linear Combinations, Parameter Estimation, and Real-World Modeling

Linear Combinations, Parameter Estimation, and Real-World Modeling

IB AA SL: core and optional content

Core: individual-height probability in(b)(i) and qualitative model discussion in(a)(i)–(ii). Optional: distribution of a sample mean in(a)(iii), total-height probability in(b)(ii) and dependent comparison.

A school has a large number of girls. For each year-group it may be assumed that the heights of girls are normally distributed, with average heights and standard deviations as given in the following table.

Year-group

Average height

Standard deviation

\(11\)-year old girls

\(1.1\) m

\(0.2\) m

\(16\)-year old girls

\(1.7\) m

\(0.3\) m

  1. For each of the following cases, state, with a reason, whether or not a normal model is likely to be appropriate.
    1. The number of days since her last birthday of a randomly chosen \(11\)-year old girl from the school.
    2. The height of a pupil chosen at random from the combined group of \(11\)-year old and \(16\)-year old girls in the school.
    3. The average height of a randomly chosen sample of eight \(11\)-year old girls from the school
  2. Find the probability such that
    1. each of the two randomly chosen \(11\)-year old girls is taller than \(1.2\) m.
    2. the total height of two randomly chosen \(11\)-year old girls is more than \(2.4\) m.

Explain why the answer to (b)(ii) is higher than that of (b)(i).

Video Solution:

Video Solution

Video solution locked

A free account saves your progress; this video needs tuition enrolment.

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs tuition enrolment.

Create a free account to practise similar questions.

Answer:(a)(i) Not appropriate: days since the last birthday are approximately uniformly distributed. (a)(ii) Not appropriate: combining the two year-groups produces a mixture that is not exactly normal; bimodality depends on the mixing proportions. (a)(iii) Appropriate: \(\overline X\sim N\left(1.1,\dfrac{0.2^2}{8}\right)\). (b)(i) \(0.0952\) (b)(ii) \(0.240\) Explanation: Event (b)(i) is a proper subset of event (b)(ii), so (b)(ii) has the greater probability.

Need help? Join our JC Math tuition classes.

Learn more