Line through a point of a curve, and its tangent case
Line through a point of a curve, and its tangent case
Secondary 3
The equation of a curve is \(y=4-x^2\) and the equation of a line is \(y=kx+3-k\), where \(k\) is a constant.
- Show that the line meets the curve for all real values of \(k\).
- Find the value of \(k\) for which the line is a tangent to the curve.
Solution:
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Answer:(a) Shown: \(D=(k+2)^2\ge0\) for every \(k\). (b) \(k=-2\).
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