Triangle $ABC$ is a right-angled triangle with angle $ACB = 90^\circ$. $CD$ is the altitude (h

Question

Triangle $ABC$ is a right-angled triangle with angle $ACB = 90^\circ$. $CD$ is the altitude (height) on side $AB$. Show that $CD^2 = AD \times BD$ $AC^2 = AD \times AB$, and $BC^2 = BD \times AB$

Accepted Answer

$\text{(i)}\ CD^2=AD\times BD$ $\text{(ii)}\ AC^2=AD\times AB$ $\text{(iii)}\ BC^2=BD\times AB$

IP2U8 HOT Q3 (Right Triangle Altitude Theorem)

IP2U8 HOT Q3 (Right Triangle Altitude Theorem)

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