In the diagram below, $\Delta ADG$ and $\Delta EHC$ overlap to form a parallelogram $BDFH$. Gi

Question

In the diagram below, $\Delta ADG$ and $\Delta EHC$ overlap to form a parallelogram $BDFH$. Given further that $AG = EC$ and $\angle HCE = \angle DGA$, prove that $\Delta ADG$ is congruent to $\Delta EHC$. State your reasons clearly.

Accepted Answer

$\triangle ADG\cong\triangle EHC\text{ (AAS)}$

IP2U8 Exercise Q4

IP2U8 Exercise Q4

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